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3 years ago

11. Which equation could you use to find the next

Mathematics

2 answers:

ankoles [38]3 years ago

5 0

Answer:

B. A(n)= 6.3n

Step-by-step explanation:

dimaraw [331]3 years ago

3 0

Answer:

B. A(n)= 6.3n

Step-by-step explanation:

6×3=18

18×3=54

54×3=162

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4 years ago

An imaginary number is not a real number

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3 years ago

Rewrite each phrase as an algebraic expression subtract 7 from c

Neko [114]

The phrase "subtract 7 from c" written in algebraic expression is c - 7

<h3>Algebraic expression</h3>

This is a system of computation using letters or other symbols to represent numbers, with rules for manipulating these symbols.

Subtract 7 from c

= c - 7

For instance, if c = 15

c - 7

= 15 - 7

= 8

Therefore, the phrase "subtract 7 from c" written in algebraic expression is c - 7

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2 years ago

Multiplying an even number of negative numbers gives an answer that is<br> choose from:

Vikentia [17]

Answer:

A positive number

Step-by-step explanation:

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4 years ago

Use Stokes' Theorem to evaluate |c F * dr where C is oriented counterclockwise as viewed from above.F(x, y, z) = xyi + 5zj + 7yk

Hunter-Best [27]

Compute the curl of $\vec F$ :

$\vec F(x,y,z)=xy\,\vec\imath+5z\,\vec\jmath+7y\,\vec k\implies\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k$

By Stoke's theorem, the (line) integral of $\vec F$ along $C$ is equivalent to the (surface) integral (or flux) of $\nabla\times\vec F$ across $S$ , the oriented surface with boundary $C$ .

Take $S$ to be the part of the plane $x+z=3$ within the cylinder $x^2+y^2=144$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(3-u\cos v)\,\vec k$

with $0\le u\le12$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=u\,\vec\imath+u\,\vec k$

Then the integral is

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^{12}(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^{12}(2u-u^2\cos v)\,\mathrm du\,\mathrm dv=\boxed{288\pi}$

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3 years ago