Answer:
A = [- 2Bl + U^2 +/- √((2BL - U^2)^2 - 4B^2L^2) ] / 2L
Step-by-step explanation:
L = U^2A / (A + B)^2
U^2 A = L(A^2 + 2AB + B^2)
U^2 A = LA^2 + 2ABL + B^2L
LA^2 + 2ABL - U^2A + B^2 L = 0
LA^2 + (2BL - U^2)A + B^2L = 0
Using the quadratic formula
A = [- (2BL - U^2) +/- √[(2BL - U^2)^2 - 4*L*B^2L] / 2L
A = [- 2BL + U^2 +/- √[(2BL - U^2)^2 - 4B^2L^2) ] / 2L
Answer: A. it’s parallel
Step-by-step explanation:
just did my test.
Let the width be x, it length is 2x - 4
Area = length x width
x(2x - 4) = 170
2x^2 - 4x - 170 = 0
x^2 - 2x - 85 = 0
x = 10.27
Therefore, the width ≈ 10.27 ft and the length is 2(10.27) - 4 ≈ 16.54
The correct answer will be B. 42, 504.
This is a trick from University and High School Statistics.
You must think you have 24 students, and must CHOOSE 5.
On a calculator you do 24C5 (or whatever your function is for combinations) and that is how you get the answer.
I only got the answer to 20. Hope this helps!
