Given: ∆AMK, MP ⊥ AK , MP = 10 m∠A = 72º, m∠PMK = 50° Find AM, MK, AK
1 answer:
Answer:
Step-by-step explanation:
The diagram of triangle AMK is shown on the attached photo. To determine AM, we would apply trigonometric ratio since triangle AMP is a right angle triangle.
Sin# = opposite/hypotenuse
Sin 72 = 10/AM
AMSin72 = 10
AM = 10/Sin72 = 10/0.9511
AM = 10.51
To determine MK,
Cos# = adjacent/hypotenuse
Cos 50 = 10/MK
MKCos50 = 10
MK = 10/Cos50 = 10/0.6428
MK = 15.6
AK = AP + KP
Tan# = opposite/adjacent
Tan 72 = 10/AP
AP tan 72 = 10
AP =10/tan72 = 10/ 3.0777 = 3.25
Tan 50 = KP/10
KP = 10tan50
KP= 10× 1.1918 = 11.918
Therefore,
AK = 3.25 + 11.918 = 15.168
You might be interested in
Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
( ) & (
)-
y - =
( x -
)
i.e. <em> y - 7= ( x- 1)</em>
<em> y - 7 = ( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.