Given: ∆AMK, MP ⊥ AK , MP = 10 m∠A = 72º, m∠PMK = 50° Find AM, MK, AK
1 answer:
Answer:
Step-by-step explanation:
The diagram of triangle AMK is shown on the attached photo. To determine AM, we would apply trigonometric ratio since triangle AMP is a right angle triangle.
Sin# = opposite/hypotenuse
Sin 72 = 10/AM
AMSin72 = 10
AM = 10/Sin72 = 10/0.9511
AM = 10.51
To determine MK,
Cos# = adjacent/hypotenuse
Cos 50 = 10/MK
MKCos50 = 10
MK = 10/Cos50 = 10/0.6428
MK = 15.6
AK = AP + KP
Tan# = opposite/adjacent
Tan 72 = 10/AP
AP tan 72 = 10
AP =10/tan72 = 10/ 3.0777 = 3.25
Tan 50 = KP/10
KP = 10tan50
KP= 10× 1.1918 = 11.918
Therefore,
AK = 3.25 + 11.918 = 15.168
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