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Mandarinka [93]
3 years ago
9

Square ABCD was translated using the rule (x. y) «-4,y + 15) to form A'B'CD. What are the coordinates of point

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

<em></em>(13,-23)<em></em>

Step-by-step explanation:

Given

Translation: (x,y) -> (x-4,y+15)

Required

Determine the pre-image of (9,-8)

In (9,8)

x = 9 and y = -8

So:

(x,y) -> (x-4,y+15)

Becomes

(9,8) ->(x-4,y+15)

By comparison:

x - 4 = 9

y + 15 = 8

Solving for (x):

x - 4 = 9

x = 9 + 4

x = 13

Solving for (y):

y + 15 = -8

y = -8 - 15

y = -23

<em>Hence, the pre -image has a coordinate of </em>(13,-23)<em></em>

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boyakko [2]

Answer:

\boxed{\sf \ \ 9x^2-18x-7 \ \  divided \ by \ (3x+1) \ is \ (3x-7) \ }

Step-by-step explanation:

Hello,

let's find a and b reals so that

9x^2-18x-7=(3x+1)(ax+b)

(3x+1)(ax+b)=3ax^2+(3b+a)x+b

we identify the terms in x^2

   9 = 3a

we identify the terms in x

   -18 = 3b + a

we identify the constant terms

   -7 = b

so ti goes with a = 9/3 = 3, b = -7

so we can write

9x^2-18x-7=(3x+1)(3x-7)

so 9x^2-18x-7 \ divided \ by \ (3x+1) \ is \ (3x-7)

hope this helps

8 0
3 years ago
HELP?! PLEASE! Which point is a reflection of7(-6.5,1) across the x-axis and y-axis?
Mandarinka [93]

Answer:

Dont need to worry

First, start off with the x-axis. -6.5, 1 becomes 6.5, 1. This is because point T is 6.5 to the left of the x-axis line, so our new point would be 6.5 to the right of the x-axis line. Same thing for the y-axis, (6.5, 1) would become (6.5, -1).

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The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
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Answer:

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From the given question, the bag contains;

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Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

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Answer:

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Step-by-step explanation:

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