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4 years ago

PLEASE HELP

Mathematics

2 answers:

iragen [17]4 years ago

5 0

Answer:

Step-by-step explanation:

These are what the symbols mean so you can better understand them

p: I like to go to the beach

q: I like to eat ice cream

r: I do not enjoy rainy days

^ = means OR so a that has or in it.

v = means AND so any sentance with and in it

~ = not so any phrase that condridicts what the origional P,Q, and/or R

∴ = Therefore so any phrase with therefore.

So; p ∧ q would be P... OR... Q acording to the key above would be

I ilke to go to the beach OR I like to eat icecream.

You can figure out the rest! Hope this helps you!

disa [49]4 years ago

3 0

Answer:

it's c. r ^ q

Step-by-step explanation:

I just did it in Edgy 2020

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Find the length of the base of a square pyramid if the volume is 128 cubic inches and has a height of 6 inches

Len [333]

Answer: a = 8

Step-by-step explanation:

Volume of a square based pyramid is given as

$\frac{a^{2}h }{3}$ .

where a is the length of the side and h is the height.

Substituting into the formula , we have

V = $\frac{a^{2}h }{3}$

128 = $a^{2}h$ /3

384= $a^{2}$ X 6

Divide through by 6

384/6 = $a^{2}$

64 = $a^{2}$

Therefore :

a = $\sqrt{\frac{64}{1} }$

a = 8

6 0

4 years ago

Can anyone explain this to me??

finlep [7]

It is the first option. DF = DE. It is referring to the lengths of each line, DE and DF look like they are the same. It is not a scalene triangle it is a right triangle. EF is way too long to be equal to DE or DF

3 0

3 years ago

A pet store employee counts 23 heads and 68 feet on the animals in the store. The store currently only has kittens and parakeets

Aloiza [94]

Answer:

11 kittens and 12 parakeets

Step-by-step explanation:

each kitten has 4 feet while each parakeet has 2

11 x 4 = 44 (kittens)

12 x 2 = 24 (parakeets)

11 + 12 is 23 which is your 23 heads.

44 + 24 is 68 which would be your feet

4 0

2 years ago

Find the general solution to each of the following ODEs. Then, decide whether or not the set of solutions form a vector space. E

Ipatiy [6.2K]

Answer:

(A) $y=ke^{2t}$ with $k\in\mathbb{R}$ .

(B) $y=ke^{2t}/2-1/2$ with $k\in\mathbb{R}$

(D) $y=k_1e^{2t}+k_2e^{-2t}+e^{3t}/5$ with $k_1,k_2\in\mathbb{R}$ ,

Step-by-step explanation

(A) We can see this as separation of variables or just a linear ODE of first grade, then $0=y'-2y=\frac{dy}{dt}-2y\Rightarrow \frac{dy}{dt}=2y \Rightarrow \frac{1}{2y}dy=dt \ \Rightarrow \int \frac{1}{2y}dy=\int dt \Rightarrow \ln |y|^{1/2}=t+C \Rightarrow |y|^{1/2}=e^{\ln |y|^{1/2}}=e^{t+C}=e^{C}e^t} \Rightarrow y=ke^{2t}$ . With this answer we see that the set of solutions of the ODE form a vector space over, where vectors are of the form $e^{2t}$ with $t$ real.

(B) Proceeding and the previous item, we obtain $1=y'-2y=\frac{dy}{dt}-2y\Rightarrow \frac{dy}{dt}=2y+1 \Rightarrow \frac{1}{2y+1}dy=dt \ \Rightarrow \int \frac{1}{2y+1}dy=\int dt \Rightarrow 1/2\ln |2y+1|=t+C \Rightarrow |2y+1|^{1/2}=e^{\ln |2y+1|^{1/2}}=e^{t+C}=e^{C}e^t \Rightarrow y=ke^{2t}/2-1/2$ . Which is not a vector space with the usual operations (this is because $-1/2$ ), in other words, if you sum two solutions you don't obtain a solution.

(C) This is a linear ODE of second grade, then if we set $y=e^{mt} \Rightarrow y''=m^2e^{mt}$ and we obtain the characteristic equation $0=y''-4y=m^2e^{mt}-4e^{mt}=(m^2-4)e^{mt}\Rightarrow m^{2}-4=0\Rightarrow m=\pm 2$ and then the general solution is $y=k_1e^{2t}+k_2e^{-2t}$ with $k_1,k_2\in\mathbb{R}$ , and as in the first items the set of solutions form a vector space.

(D) Using C, let be $y=me^{3t}$ we obtain that it must satisfies $3^2m-4m=1\Rightarrow m=1/5$ and then the general solution is $y=k_1e^{2t}+k_2e^{-2t}+e^{3t}/5$ with $k_1,k_2\in\mathbb{R}$ , and as in (B) the set of solutions does not form a vector space (same reason! as in (B)).

4 0

4 years ago

Anyone knows this answer ?

jok3333 [9.3K]

Rise over run is 6/4

8 0

3 years ago