For all real numbers a and b, 2a•b=a^2 + b^2
2 answers:
That's not true at all.
If a=2 and b=3 . . . then
2 · a · b = 12
but
a² + b² = 13 .
This doesn't satisfy your statement, because 12 and 13 are not equal.
Right off hand, it looks to me as if your statement is true
ONLY if
|a| = |b| ('a' = plus or minus 'b')
and NOT for any other pairs of numbers.
Hmm
one solutionm is if both a and b were 0
the resulting equation would be 0=0 which is true
(0,0) is one solution
another is if both a and b are 1
resulting equation would be 2=2 which is true
I just graphed it and the solution is all values such that a=b
so
(a,b)
(1,1)
(2,2)
(π,π)
etc
(1,1) is a solution
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