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Rom4ik [11]
4 years ago
12

For all real numbers a and b, 2a•b=a^2 + b^2

Mathematics
2 answers:
fiasKO [112]4 years ago
7 0
That's not true at all.

If  a=2  and  b=3 . . .  then

             2 · a · b = 12
but
            a²  +  b²  =  13 .

This doesn't satisfy your statement, because 12 and 13 are not equal.

Right off hand, it looks to me as if your statement is true
ONLY if 
                   |a|  =  |b|                 ('a' = plus or minus 'b') 

and NOT for any other pairs of numbers.
shepuryov [24]4 years ago
5 0
Hmm

one solutionm is if both a and b were 0
the resulting equation would be 0=0 which is true
(0,0) is one solution

another is if both a and b are 1
resulting equation would be 2=2 which is true

I just graphed it and the solution is all values such that a=b
so
(a,b)
(1,1)
(2,2)
(π,π)
etc
(1,1) is a solution
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Irina-Kira [14]

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The answer to your question is   -3, 7

Step-by-step explanation:

Data

                    x  +  y  = 4   ------------ Equation l

                  7x + 9y  = 42 -----------  Equation ll

Process

1.- Solve the system by elimination

- Multiply equation l by -7

                  -7x - 7y = - 28

                    7x+9y =   42

2.- Simplify

                   0  + 2y = 14

3.- Solve for y

                            y = 14/2

                           y = 7

4.- Substitute y in equation l to find x

                      x  + 7 = 4

Solve for x

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Step-by-step explanation:

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Vitek1552 [10]

Answer:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

This agrees with the last option in the list of possible answers

Step-by-step explanation:

Recall that the maximum of a parabola resides at its vertex. So let's find the x and y position of that vertex, by using first the fact that the x value of the vertex of a parabola of general form:

y=ax^2+bx+c

is given by:

x_{vertex}=\frac{-b}{2\,a}

In our case, the quadratic expression that generates the parabola is:

y=-2x^2+24x+174

then the x-position of its vertex is:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{-24}{2\,(-2)}\\x_{vertex}=\frac{-24}{-4)}\\x_{vertex}=6

This is the price of the video game that produces the maximum profit (x = $6). Now let's find the y-position of the vertex using the actual equation for this value of x:

y=-2x^2+24x+174\\y_{vertex}=-2\,(6)^2+24\,(6)+174\\y_{vertex}=-72+144+174\\y_{vertex}=246

This value is the highest weekly profit (y = $246).

Now, recall that we can write the equation of the parabola in what is called "vertex form" using the actual values of the vertex position (x_{vertex},y_{vertex}):

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-246=-2\,(x-6)^2\\y=-2\,(x-6)^2+246

Therefore the answer is:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

6 0
3 years ago
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