The answer would be 31.83! <3
Answer:
For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Step-by-step explanation:
The score of students in last 3 exams = 89 , 87 and 92
Let us assume the marks scored by the student in last exam = k
The average of marks should be above 90.
Now, 
Sum of all 4 paper's marks = 89 + 87 + 92 + k = 268 + k
Also, 90 < Average

Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
6x+33-2(3x+1)
17+14
30+1
60-29
18+13
Answer:
C'
Step-by-step explanation:
Given
ABCD to A'B'C'D'
Required
Corresponding angle of C
ABCD to A'B'C'D' means that the following angles are corresponding




Hence, C' corresponds to C