7 books with a cost of 28$ then a 2$ charge which will put him right at 30
90 days.
For this question you just need to find the least common multiple of 18 and 30. That can be found by first finding the prime factorization of each number. 18 = 2 * 3 * 3 and 30 = 2 * 3 * 5. Then you multiply the 2 * 3 * 3 * 5, you ignore the 3 from 30 because 18 has more 3s. The answer is 90.
Answer:
The minimum value of f(x) is -21 and it occurs at x = 1
Step-by-step explanation:
f(x) =3x^2-6x-18
Factor out the greatest common factor out of the first two terms
f(x) =3(x^2-2x)-18
Complete the square
-2x/2 =-1 (-1)^2 = 1
Add 1 (But remember the 3 out front so we are really adding 3 so we need to subtract 3 to remain balanced)
f(x) = 3(x^2 -2x+1) -3 -18
f(x) = 3(x-1)^2 -21
This is vertex form
f(x) = a(x-h)^2 +k where (h,k) is the vertex and a is a constant
The vertex is (1,-21)
Since a > 0 this opens upward and the vertex is a minimum
The minimum value of f(x) is -21 and it occurs at x = 1
Answer:
k > -26
Step-by-step explanation:
To isolate the k, you subtract 6 from both sides to get k < -26.
Answer:
--16 1/14, -225/14 or -16.07
Step-by-step explanation:
3/4(2x+5)=5(x+12)
3x/2+15/4=5x+60
-225/14
