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2 years ago

there are three choices of jellybeans - grape ,cherry and orange. if the probability of getting a grape is 3/a0

1 answer:

5 0

What would the a represent I don't get it. If the probability of getting grape 3% so the probability of getting another color is 48.5%.

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Find the total cost of a $43 dinner if you leave 18% gratuity (tip).

AleksandrR [38]

50.74
B/c 43*.18=7.74
7.74+43=50.74

hope this helps

8 0

2 years ago

Which of the following systems of inequalities has point D as a solution? Two linear functions f of x equals 3 times x plus 4 an

Pani-rosa [81]

Answer:

B) f(x) ≥ 3x + 4

g of x is less than or equal to negative one half times x minus 5

Step-by-step explanation:

From the above graph,

If point B is the solution of the system of inequalities, then point B must satisfies both inequalities

We can see from the graph that

Point B is located above (≥) the boundary line for f(x) and is also below (≤) the boundary line for g(x).

So we can say,

Point b satisfies the inequalities

Therefore,

The system is

f(x) ≥ (3x+4)

g(x) ≤ (-1/2x -5)

Hopes this Helps :)

8 0

2 years ago

How many computers must the AB Computer Company sell to break even? Let x be the number of computers.

Eduardwww [97]

Answer:

The Company AB must sell 116 computers to break even

Step-by-step explanation:

we have

$R(x)=1.5x$ -----> equation A

$C(x)=145+\frac{1}{4}x$ ----> equation B

where

C is the cost function

R is the revenue function

x is the number of computers sold

we know that

Break even is when the cost is equal to the revenue

equate equation A and equation B

$1.5x=145+\frac{1}{4}x$

Solve for x

subtract 1/4x both sides

$1.5x-\frac{1}{4}x=145$

$1.5x-0.25x=145$

$1.25x=145$

Divide by 1.25 both sides

$x=116$

therefore

The Company AB must sell 116 computers to break even

7 0

2 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

2 years ago

Which segment are parallel select each correct answer

Kamila [148]

AB would be your answer

5 0

2 years ago

Read 2 more answers