Answer:
Decimal form:
2.10526315789
Step-by-step explanation:
Answer:
80/81
Step-by-step explanation:
If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.
The probability of getting at least 1 head involves 4 scenarios:
1) 1 Head and 3 Tails
2) 2 Heads and 2 Tails
3) 3 Heads and 1 Tail
4) 4 Heads
Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:
P(at least one head) + P(no heads) = 1
Then, P(at least one head) = 1 - P(no heads)
The probability of 4 tails is:
P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81
Then, P(at least one head) = 1 - 1/81=80/81
Answer:
2×π×(1/2)L×L+2×π×((1/2)L)^2
Step-by-step explanation:
perimeter of cross-section × height +2× area of cross-section
Answer:
8
Step-by-step explanation:
First find all factors of 72 and 64 and put them in their respective circles
The factors of 72: 1,2,3,4,6,8,9,12,18,24,36,72
The factors of 64: 1,2,4,8,16,32,64
Now find the factors that both numbers share.
Common factors: 1,2,4,8
The greatest common factor of 72 and 64 is 8.