Answer:
D) x = -2/3 and x = 6
Step-by-step explanation:
4(x²−x+2)−(x+10)(x+2) Distribute
(4)(x²) + (4)(−x) + (4)(2) + − x² + −12x + −20 Multiply
4x² + −4x + 8 + −x² + −12x + −20 Combine like terms
(4x² + −x²) + (−4x + −12x) + (8 + −20) Combine like terms
3x² −16x −12 = 0
x = -2/3 and x = 6
I graphed the equation on the graph below.
If this answer is correct, please make me Brainliest!
simplify
n-2 = 10n/2 + 4/2
n-2 = 5n + 2
subtract 5n to both sides
n - 2 - 5n = 5n + 2 - 5n
simplify
-4n - 2 = 2
add 2 to both sides
-4n - 2 + 2 = 2 + 2
simplify
-4n = 4
divide both sides by -4
-4n/-4 = 4/-4
simplify
n = -1
hope it helps
Answer:
1. Use a compass to make arc marks which intersect above and below then connect.
2. 
Step-by-step explanation:
1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.
2. The point slope form of a line is
where
. We write
Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.
Simplify for slope intercept form.

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:
![CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack%20x-Z_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%2Cx%2BZ_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%5Crbrack)
Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:
![CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack30.0-Z_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%2C30.0%2BZ_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%5Crbrack)
Where (from tables):

Finally, the interval at 98% confidence level is:
The intersection of two sets is a set that contains elements that are common to both sets.
There are no common elements in sets E and F, so the answer is the empty set.
<span>E ∩ F = { }</span>