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podryga [215]
3 years ago
10

Please help me graph #9.

Mathematics
2 answers:
Allisa [31]3 years ago
6 0

Answer:

f(4)=1 as X>1

f(0)=4 as (-3 is less than or equal to X greater than or equal to 1)

f(-3) = 4 (-3 is less than or equal to X greater than or equal to 1)

Nata [24]3 years ago
4 0
Hint to start out the problem:

eg. For f(4), use the first expression, (x-3)^2 because 4 is greater than 1.
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Please answer both questions i will fail if i don't get these
MrRa [10]

Answer:

its  below

Step-by-step explanation:

a) (0,1)   (-1,2)  (1,2)  (2,5)   (-2,5)

b) (0, -1, 1, 2, -2)

c) (1,2,5,5)

#4 a)  f(-5) = 39

b) f(1) = -9

4 0
3 years ago
Celeste needs to create a keyword map that branches out from an image of the solar system. Which image best
Veseljchak [2.6K]

Answer:

The Correct Answer Is C

Step-by-step explanation:

4 0
3 years ago
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
Write seven hundred two and six hundred fifty-six thousandths in standard form and in expanded form.
Naddik [55]
Standard Form: 702.656
Expanded Form: 700+2+0.6+0.05+0.006
7 0
3 years ago
One sixth plus negative seven ninths
OLga [1]

Answer:

-11/18

Step-by-step explanation:

1. find the common denominator. this should be 18

2. multiply 1 by 3 and -7 by 2

3. you should now have a fraction that says 3/18-14/18

4. now subtract these two fractions.

5. your answer should be -11/8

8 0
2 years ago
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