Which of the following ordered pairs does not lie on the graph of y=log_(2)^x? (1/2, -1) (0, 1) (1, 0)
2 answers:
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Answer:
x =
Step-by-step explanation:
Given
+
= 1
Multiply through by ab to clear the fractions
bx + ax = ab ← factor out x from each term on the left side
x(b + a) = ab ← divide both sides by (b + a)
x =
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
