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ANEK [815]
3 years ago
6

Use a calculator to evaluate sec 85 degrees

Mathematics
1 answer:
faltersainse [42]3 years ago
3 0

OK.  I used my calculator to evaluate sec(85 degrees).

My calculator doesn't have a "sec" button on it. 
But I remembered that

           sec of an angle = 1 / (cosine of the same angle) .

So I used my calculator to find cos(85), and then I hit the
" 1/x " key, and got 11.474, which I knew to be sec(85).

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irga5000 [103]
Let the cost of one pound of candy be x and one pound of mint be y.

3x+2y=10.8 a 
x+3y = 5.35  b 
 B*3 = 3x+9y = 16.05 b
 
b-a = 7y = 16.05-10.8= 5.25
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The cost per pound of mints is $0.75 


6 0
3 years ago
Which shape is similar to the original shape?<br> A) A <br> B) B <br> C) C <br> D) D
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Answer:

I think the answer is A.

Step-by-step explanation:

Original shape: 7 x 5 x 225 x 6 x 12 x 45 = 25,515,000

A: 9 x 5 x 225 x 6 x 35 x 12 = 25,515,000

B: 14 x 10 x 255 x 12 x 24 x 45 = 462,672,000

C: 9 x 7 x 225 x 8 x 15 x 45 = 76,545,000

D: 8 x 4 x 225 x 6 x 12 x 35 = 18,144,000

This is probably not the way you would solve it but this is how I did it. Basically I multiplied all the numbers in each shape together.

<em>(also i'm not quite sure if this is right >.< sorry!)</em>

8 0
3 years ago
John borrowed a certain amount of money from Tebogo at a simple interest rate of 8,7% per year. 
Anestetic [448]

Answer:

Step-by-step explanation:

5 0
3 years ago
Convert and round to the proper Precision or accuracy. 21.4 grams= mg? * O .0214 mg О 214 mg О 214.0 mg O 21,400 mg 00214 mg​
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4 0
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This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

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There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

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3 0
3 years ago
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