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3 years ago

Urgent please hell..

Mathematics

1 answer:

vovikov84 [41]3 years ago

6 0

8 x (3^2/4^2)
=4.5
........................

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Find 85% of the number 33.51 help

Makovka662 [10]

33.51 X 85% (0.85) = 28.48

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3 years ago

Read 2 more answers

A water balloon is tossed into the air. The function h(x)=-0.5(x-4)squared +9 gives the height, in the feet, of the balloon from

NNADVOKAT [17]

Answer:

No, the maximum height that the balloon can reach is 9ft.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

The function h(x) =-0.5(x-4)² +9, is a Quadratic Function in the Vertex form.

Vertex form: f (x) = a(x - h) 2 + k

Where:

(h, k) is the vertex of the parabola-

h is the horizontal shift (how far left, or right, the graph has shifted from x = 0).

k represents the vertical shift (how far up, or down, the graph has shifted from y = 0).

In this case a = -0.5, it means that the parabola opens downward and has a maximum point at the vertex.

So, the maximum height that the balloon can reach is k=9ft.

9 ∠ 12

The balloon will not hit the ceiling 12 ft above the pool.

Feel free to ask for more if needed or if you did not understand something.

8 0

3 years ago

What is the volume of the cone? use 3.14

Svet_ta [14]

To find the volume of the cone use the formula:

3.14r^2 h/3

Final Answer:

20.93 cubic units

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3 years ago

15 points!!! GEOMETRY help please!!<br> Questions attached!

dolphi86 [110]

3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

$x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o$

$Answer:\ \boxed{47^o}$

4.
Look at the picture.

Use Pythagorean theorem:

$x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8$

$Used:\ (a+b)^2=a^2+2ab+b^2$

$Answer:\ \boxed{4.8\ units}$

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}$

We have: $OP:\ y=-\dfrac{3}{2}x+b$

Now, we must find the slope of the line perpendicular to the line OP.
We know:

$k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1$

therefore

$-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}$

So. We have the answer! :)

$Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}$

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3 years ago

I'm struggling on this problem . Find the area of this figure

nignag [31]

Answer:

figure please...... I cant see the figure

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3 years ago