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Nutka1998 [239]
3 years ago
15

Solve Quantity 9 plus x end quantity over 3x is equal to five-sixths. Show all work.

Mathematics
2 answers:
Semenov [28]3 years ago
4 0
(9+x)/3x = 5/6
(9+x)/x = 15/6             (then distribute out x on bottom)
9/x + 1 = 15/6
9/x = 1.5
x = 9/1.5
x=6

Free_Kalibri [48]3 years ago
3 0
Remember you can do anything to an equation as long as you do it to both sides

\frac{9+x}{3x}=\frac{5}{6}
multiply both sides by (3x)(6)   (basically cross multiply)
(6)(9+x)=(5)(3x)
distribute
54+6x=15x
minus 6x both sides
54=9x
divide both sides by 9
6=x
x=6
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Step-by-step explanation:

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Simplify the integrands by polynomial division.

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5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

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5 0
2 years ago
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