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3 years ago

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Y is inversely proportional to the square of x. If Y = 9 when x = 2, then what is y, when x is 10?

1 answer:

a_sh-v [17]3 years ago

5 0

Answer:

y = 0.36

Step-by-step explanation:

Given y is inversely proportional to x² then the equation relating them is

y = $\frac{k}{x^2}$ ← k is the constant of variation

To find k use the condition y = 9 when x = 2 , then

9 = $\frac{k}{2^2}$ = $\frac{k}{4}$ ( multiply both sides by 4 )

36 = k

y = $\frac{36}{x^2}$ ← equation of variation

When x = 10 , then

y = $\frac{36}{10^2}$ = $\frac{36}{100}$ = 0.36

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

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(b)

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(c)

$(-5^{-3})^{-1}=-125$

(d)

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Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

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(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

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4 0

3 years ago

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choli [55]

Answer:

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Step-by-step explanation:

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3 years ago