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3 years ago

Y is inversely proportional to the square of x. If Y = 9 when x = 2, then what is y, when x is 10?

Mathematics

1 answer:

a_sh-v [17]3 years ago

5 0

Answer:

y = 0.36

Step-by-step explanation:

Given y is inversely proportional to x² then the equation relating them is

y = $\frac{k}{x^2}$ ← k is the constant of variation

To find k use the condition y = 9 when x = 2 , then

9 = $\frac{k}{2^2}$ = $\frac{k}{4}$ ( multiply both sides by 4 )

36 = k

y = $\frac{36}{x^2}$ ← equation of variation

When x = 10 , then

y = $\frac{36}{10^2}$ = $\frac{36}{100}$ = 0.36

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