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oee [108]
3 years ago
6

Y is inversely proportional to the square of x. If Y = 9 when x = 2, then what is y, when x is 10?

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer:

y = 0.36

Step-by-step explanation:

Given y is inversely proportional to x² then the equation relating them is

y = \frac{k}{x^2} ← k is the constant of variation

To find k use the condition y = 9 when x = 2 , then

9 = \frac{k}{2^2} = \frac{k}{4} ( multiply both sides by 4 )

36 = k

y = \frac{36}{x^2} ← equation of variation

When x = 10 , then

y = \frac{36}{10^2} = \frac{36}{100} = 0.36

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