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oee [108]
3 years ago
6

Y is inversely proportional to the square of x. If Y = 9 when x = 2, then what is y, when x is 10?

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0

Answer:

y = 0.36

Step-by-step explanation:

Given y is inversely proportional to x² then the equation relating them is

y = \frac{k}{x^2} ← k is the constant of variation

To find k use the condition y = 9 when x = 2 , then

9 = \frac{k}{2^2} = \frac{k}{4} ( multiply both sides by 4 )

36 = k

y = \frac{36}{x^2} ← equation of variation

When x = 10 , then

y = \frac{36}{10^2} = \frac{36}{100} = 0.36

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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8 0
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

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(b)

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(c)

(-5^{-3})^{-1}=-125

(d)

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Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

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(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

4 0
3 years ago
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choli [55]

Answer:

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Step-by-step explanation:

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