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melisa1 [442]
3 years ago
8

Tickets to the zoo cost $14 for adults and $10 for children. A group of 12 people went to the zoo, and the tickets cost $140. Th

e system of equations models this situation, where x is the number of adults and y is the number of children.
x+y=12
14x+10y=140
How many adults and how many children were in the group?

A.
5 adults and 7 children

B.
6 adults and 6 children

C.
7 adults and 5 children

D.
8 adults and 4 children
Mathematics
1 answer:
hjlf3 years ago
8 0
 x is the number of adults and y is the number of children.
   x + y = 12
<span>14x + 10y = 140
lets multiply the first equation by -10 and then add it to the second equation:
-10x - 10y = -120
</span>14x + 10y = <span>140
</span>-----------------------
4x + 0 = 20
x = 20/4
x = 5
then substitute in the original equation:
x + y = <span>12
</span>5 + y = <span>12
</span>y = 12 - 5
y = 7
therefore there were 5 adults and 7 children
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Answer:

28

Step-by-step explanation:

x=blue

y=white

x+y=40

30x+20y=920

30(x+y=40) ; 30x+30y=1200___[1]

30x+20y=920 ; 30x+20y=920___[2]

[1]-[2] : 30x+30y-30x-20y=1200-920

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2 years ago
Write an equation for the nth term of<br> the arithmetic sequence: <br> 15,28,41 ....
11111nata11111 [884]

Answer:

The equation for the nth term of  the given arithmetic sequence is: \mathbf{a_n=13n+22}

Step-by-step explanation:

We need to write an equation for the nth term of  the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: a_n=a_1+(n-1)d

Where a_n is the nth term, a_1 is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13

So, the common difference d is 13

Now, equation for nth term will be:

a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2

So, the equation for the nth term of  the given arithmetic sequence is: \mathbf{a_n=13n+22}

where n=1,2,3..

4 0
2 years ago
Someone please help me
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3 years ago
(0.2c^3)^2–0.01c^4(4c^2–100)
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3 0
3 years ago
Read 2 more answers
A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
3 years ago
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