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Vedmedyk [2.9K]
3 years ago
14

What is the domain of -3x^(1/3)+4x^(1/2)

Mathematics
1 answer:
GrogVix [38]3 years ago
8 0
The domain of the function would be [0, ∞)

This is because of the x^(1/2);  this is the same as the square root of x. Remember:  if x is under the square root, then x can't be negative because negatives do not have square roots.  X can be 0, because the square root of 0 is 0, and of course it can be positive.  So, x can be anywhere from 0 to infinity including 0.
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Answer:

C

Step-by-step explanation:

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Give an odd function which of following transformations would result in an odd function
tamaranim1 [39]

Answer: Reflection across the x-axis and Vertical stretch are the ones that return an odd function.

Step-by-step explanation:

An odd function f(x) is a function such that:

f(-x) = -f(x).

So let's analyze the options:

A) Horizontal translation.

An horizontal translation of A units to the right (A > 0) is written as:

g(x) = f(x  - A)

Now, let's see if g(x) is also odd.

g(x) = f(x - A)

g(-x) = f(-x - A)

Now, f(-x - A) is equal to -f( x + A)

then:

g(-x) = f(-x - A) ≠ -g(x) = -f(x - A)

This is not an odd function.

B) Reflection over the x-axis.

When we have a point (x, y), a reflection over the x-axis changes the sign of the y-variable.

Then we have that:

g(x) = -f(x).

Then:

g(x) = -f(x)

g(-x) = -f(-x) = -(-f(x)) = f(x)

then:

g(x) = -f(x) = -g(-x)

This is an odd function.

C) Vertical stretch:

We can write a vertical stretch of factor scale A as:

g(x) = A*f(x).

Let's see if g(x) is odd:

g(-x) = A*f(-x) = A*(-f(x)) = -A*f(x) = -g(x)

this is a odd function.

C) Vertical translation:

A vertical translation of A units up (A > 0) is written as:

g(x) = f(x) + A.

Similar to the case of the horizontal translation, so it is easy to see that g(x) is not an odd function.

8 0
4 years ago
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Step-by-step explanation:

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