Answer:
The largest possible weight of flour is 11.25 pounds.
Step-by-step explanation:
To start with, we will assume that the weight of 1 sack of sugar = x pounds
We will also assume that the weight of 1 sack of flour = y pounds
So, the weight of 2 sacks of sugar = 2 * (x) = 2x
Same thing goes for the weight of 3 sacks of flour = 3 * (y) = 3y
Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds
= 2x + 3y ≤ 40............ we'll call that equation 1.
Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds
= y ≤ 2x + 5........................ we'll call that equation 2
Therefore, we'll solve for the values of x and y in the two equations and we will get:
2x + 3y ≤ 40
y ≤ 2x + 5
Now, substitute the value of y into equation 1
2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40
⇒ 2x + 6x + 15= 40
⇒ 8x + 15 = 40
⇒ 8x = 25
⇒ x = 25/8
⇒ x = 3.12
x cannot be more than 3.12 pounds, so we solve for y
Putting the value of x into equation 2, we'll get
⇒ 2y + 5 = 2(3.12) + 5
⇒ y = 11.25 pounds.
So, n cannot be more than 11.25 pounds
