Answer:
560.00
Step-by-step explanation:
im really not sure
Answer:
u gotta divide the 7.5% and the other number that is says (can see the question but there)
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
1. 18
2. -8
3. 1
4. 84
Step-by-step explanation:
hope this helps! :D
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