Well there can be two different solutions for this but i will choose the easier one. Obviously one requires a system of equations which obviously will involve a lot of thinking and some good algebra solving in order for them to solve.
So we can just keep adding the distance as we know they are in different directions. 49 + 65 = 114. So 114 * 4.5 = 513 miles. SO after around 4.5 hours they will be 513 miles apart.
Answer:
B. 
Step-by-step explanation:
We have been given that the trapezoid shown in the attachment has been enlarged by a scale of 1.5. We are asked to find the area of the enlarged trapezoid.
The area of the original trapezoid is 36 square inches.
Since each side of the trapezoid is enlarged 1.5 times, so the area of new trapezoid would be 2.25 times greater than area of original trapezoid.
The area would be 2.25 times greater because area is product of sum of lengths of parallel sides and height.
Therefore, the area of the enlarged trapezoid would be and option B is the correct choice.
Answer:
Step-by-step explanation:
The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).
The slope of side AB is
The slope of side BC is
The slope of side CD is
The slope of AD is
We see that the opposite sides of the quadrilateral ABCD are equal.
Hence the quadrilateral is a parallelogram
Both the general shape of a polynomial and its end behavior are heavily influenced by the term with the largest exponent. The most complex behavior will be near the origin, as all terms impact this behavior, but as the graph extends farther into positive and/or negative infinity, the behavior is almost totally defined by the first term. When sketching the general shape of a function, the most accurate method (if you cannot use a calculator) is to solve for some representative points (find y at x= 0, 1, 2, 5, 10, 20). If you connect the points with a smooth curve, you can make projections about where the graph is headed at either end.
End behavior is given by:
1. x^4. Terms with even exponents have endpoints at positive y ∞ for positive and negative x infinity.
2. -2x^2. The negative sign simply reflects x^2 over the x-axis, so the end behavior extends to negative y ∞ for positive and negative x ∞. The scalar, 2, does not impact this.
3. -x^5. Terms with odd exponents have endpoints in opposite directions, i.e. positive y ∞ for positive x ∞ and negative y ∞ for negative x ∞. Because of the negative sign, this specific graph is flipped over the x-axis and results in flipped directions for endpoints.
4. -x^2. Again, this would originally have both endpoints at positive y ∞ for positive and negative x ∞, but because of the negative sign, it is flipped to point towards negative y ∞.
