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zhenek [66]
3 years ago
9

Solve for x. 9(x + 1) = 25 + x x = 2 x = 3 x=4 x = 5 O

Mathematics
2 answers:
Marta_Voda [28]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

9x+9=25+x

9x-x=25-9

8x=16

x=2

bonufazy [111]3 years ago
4 0
X is equal to 2

So u do 25-9 and 9x-x and 8x is 16 and divide by 2
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Complete the chart to find the mean, variance, and standard deviation. Remember to use commas and round numbers to the nearest t
vitfil [10]

Answer: The mean of the data is 433.75, variance of the data is 99667.19 and the standard deviation of the data is 315.7011.

Explanation:

The given data is 900, 35, 500 and 300.

The number of observation is 4.

Formula of mean is,

\text{Mean}=\frac{\text{Sum of observations}}{\text{Number of observations}}

\bar{X}=\frac{900+35+50+300}{4} =433.75

The formula of variance is given below,

\sigma^2=\frac{1}{n}\sum{(X-\bar{X})^2}

\sigma^2=\frac{398668.75}{4}

\sigma^2=99667.19

The variance of the data is 99667.19

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The standard deviation of the data is 315.7011.

The other information or values of given chart is shown in the attached table.

8 0
3 years ago
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The church's goal for the fundraiser was $18,000. They exceeded their goal by 8%. How much money did they raise?
stepan [7]

Answer:

Step-by-step explanation:

18000(1+8/100)

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19440

7 0
3 years ago
A radio station broadcasts a signal over an area with a 120-mile diameter. The population density of the area is 100 people per
Leya [2.2K]
Determine the area of the circular region that can be reached by the radio station signal using the equation.
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A is area and D is diameter. Using 3.14 as pi value. 
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4 years ago
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irina [24]

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6 0
3 years ago
Find the Horizontal Tangent for x^3/3+3x^2-16x+9
bazaltina [42]

Answer:

The two horiz. tang. lines here are y = -3 and y = 192.

Step-by-step explanation:

Remember that the slope of a tangent line to the graph of a function is given by the derivative of that function.  Thus, we find f '(x):

f '(x) = x^2 + 6x - 16.  This is the formula for the slope.  We set this = to 0 and determine for which x values the tangent line is horizontal:

f '(x) = x^2 + 6x - 16 = 0.  Use the quadratic formula to determine the roots here:  a = 1; b = 6 and c = -16:  the discriminant is b^2-4ac, or 36-4(1)(-16), which has the value 100; thus, the roots are:

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x = ----------------------------------- = 2 and -8.

                         2

Evaluating y = x^3/3+3x^2-16x+9 at x = 2 results in y = -3.  So one point of tangency is (2, -3).  Remembering that the tangent lines in this problem are horizontal, we need only the y-coefficient of (2, -3) to represent this first tangent line:  it is y = -3.

Similarly, find the y-coeff. of the other tangent line, which is tangent to the curve at x = -8.  The value of x^3/3+3x^2-16x+9 at x = -8 is  192, and so the equation of the 2nd tangent line is y=192 (the slope is zero).


3 0
3 years ago
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