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kherson [118]
3 years ago
7

What is x-3y=-6 in slope intercept form

Mathematics
2 answers:
lana [24]3 years ago
4 0
Slope intercept form is y=mx+b
x-3y=-6
-3y= -x-6 (subtracted x on both sides)
y= 1/3x+2 (divided by -3 on both sides)

y=1/3x+2
DiKsa [7]3 years ago
3 0
The slope intercept form is: y = -x/3 + 2
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Which set of shapes could be used to form a net for a square pyramid?
bulgar [2K]

Answer:

A.1 square and 4 triangles

Step-by-step explanation:

A pyramid has sides that are triangular faces and a base. In a square pyramid, the base is a square.

The net therefore has 1 Square and 4 Triangles.

A net is given in the attached diagram:

8 0
3 years ago
-2 4/5 + 1/4 equals what ?
vlada-n [284]
Hey there! :)

Since 2 4/5 is greater than 1/4, the answer is negative.

You can just subtract 2 4/5 and 1/4 and add the (-) sign

2 4/5 - 1/4

Change the fractions so they can have a common denominator: 20

2 4/5 = 2 16/20

1/4 = 5/20

2 16/20 - 5/20 = 2 11/20

Add the (-) sign → -2 11/20

Answer ⇒ -2 11/20

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5 0
2 years ago
In circle o, mZWBY = 72°.
likoan [24]

Answer:

Answer is B. 36 degrees

Step-by-step explanation:

From the diagram,

angle WBY = 2 × angle WXY

angle WBY = 72°

angle WXY =

\frac{angle \: WBY}{2}

=  \frac{72}{2}

= 36 \: degrees

7 0
3 years ago
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3 years ago
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Hello everyone, could you please solve this problem step by step. I don't have the exact solution and there are no options for i
lara31 [8.8K]

Answer:

<em>The area of the shaded part  = 61.46</em>

<em />

Step-by-step explanation:

Assume the hypotenuse of the triangle is c (c>0)

As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.

The hypotenuse of the triangle can be calculated by Pythagoras theorem as following: c^{2} =a^{2} +b^{2} =(2\sqrt{5}) ^{2} + (4\sqrt{5}) ^{2} = 20 + 80 = 100

=> c = 10

So that the semi circle has the diameter = 10 => its radius = 5

  • The total area of 2 semi circles is equal to the area of the circle with radius =5

    => The total area of 2 semi circles is: \pi x 5^{2} = 25\pi

  • The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x 2\sqrt{5\\ x 4\sqrt{5} = 20

    => The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40

  • The area of the square is: c^{2} = 10^{2} =100

It can be seen that:

<em>The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles </em>

<em>= 100 -  25</em>\pi<em> + 40 = 61.46</em>

6 0
3 years ago
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