Answer:
The population size is 55.9597 (≅ 56)
Step-by-step explanation:
Since the population of protozoa develops at a constant growth rate of 0.4416 per member per day.
Then;
Day 0 = 3
Day 1 = 3 + (3 x 0.4416) = 4.3248
Day 2 = 4.3248 + (4.3248 x 0.4416) = 6.2346
Day 3 = 6.2346 + (6.2346 x 0.4416) = 8.9878
Day 4 = 8.9878 + (8.9878 x 0.4416) = 12.9568
Day 5 = 12.9568 + (12.9568 x 0.4416) = 18.6785
Day 6 = 18.6785 + (18.6785 x 0.4416) = 26.9269
Day 7 = 26.9269 + (26.9269 x 0.4416) = 38.8178
Day 8 = 38.8178 + (38.8178 x 0.4416) = 55.9597
After eight days, the population size would be 55.9597 (≅ 56).
Answer:
22/35
Step-by-step explanation:
width/length = 66/105 = 22/35
Answer:
25%
Step-by-step explanation:
16 x 100 ÷ 64.
you simply take the minutes that he exercised and thereafter divide it by the recommended exercise that was prescribed by his coach.
Let x% be the salt concentration of first solution.
Then in 8ml, amount of salt = ![\frac{8x}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B100%7D)
Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.
amount of salt in 11ml of 47% salt solution is
= ![\frac{517}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B517%7D%7B100%7D)
So, total amount of salt in new mixture = ![\frac{8x}{100} +\frac{517}{100} = \frac{8x+517}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B100%7D%20%2B%5Cfrac%7B517%7D%7B100%7D%20%3D%20%5Cfrac%7B8x%2B517%7D%7B100%7D)
But given that this new solution is a 43% salt solution.
Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is ![\frac{19*43}{100} = \frac{817}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B19%2A43%7D%7B100%7D%20%3D%20%5Cfrac%7B817%7D%7B100%7D)
Hence ![\frac{8x+517}{100} = \frac{817}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%2B517%7D%7B100%7D%20%3D%20%5Cfrac%7B817%7D%7B100%7D)
8x+517 = 817
8x=817-517 = 300
x= 300/8 = 37.5
Hence the salt concentration in the first solution is 37.5%