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3 years ago

The hypotenuse of a 45 -45 -90 triangle measures 18 cm.

Mathematics

1 answer:

meriva3 years ago

6 0

Answer:

it is not D

Step-by-step explanation:

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2. ANSWER=

mixas84 [53]

Answer:

a yes udjwjwjwjwjwjwjwjwjw

yes men es chef

6 0

3 years ago

Solve the inequality -×/2 <4

photoshop1234 [79]

Multiply by -2.
x > -8

_____
Multiplying or dividing by a negative number causes the direction of the relationship to change.

5 0

3 years ago

Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.

Ira Lisetskai [31]

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!!!PLZ HELP!!!! An expression is shown below: 3pf2 − 21p2f + 6pf − 42p2 Part A: Rewrite the expression by f

Lesechka [4]

Answer:

See below.

Step-by-step explanation:

So, we have:

$3pf^2-21p^2f+6pf-42p^2$

PART A:

Find the GCF. Notice that we have a 3 in every term and a p in every term. Thus, the GCF is 3p:

$3p(f^2-7pf+2f-14p)$

This is the most we can do.

PART B:

Continue from where we left off. Factor the entire expression:

$3p(f^2-7pf+2f-14p)\\3p(f(f-7p)+2(f-7p))\\3p((f+2)(f-7p))$

7 0

3 years ago

Suppose that the bacteria in a colony grow unchecked according to the Law of Exponential Change. The colony starts with 1 bacter

inn [45]

Answer: There are 2.25×10³⁴ bacteria at the end of 24 hours.

Step-by-step explanation:

Since we have given that

Number of bacteria initially = 1

It triples in number every 20 minutes.

So, $\dfrac{20}{60}=\dfrac{1}{3}$

So, our equation becomes

$y=y_0e^{\frac{1}{3}k}\\\\3=1e^{\frac{1}{3}k}\\\\\ln 3=\dfrac{1}{3}k\\\\k=\dfrac{1.099}{0.333}=3.3$

We need to find the number of bacteria that it will contain at the end of 24 hours.

So, it becomes,

$y=1e^{24\times 3.3}\\\\y=e^{79.1}\\\\y=2.25\times 10^{34}$

Hence, there are 2.25×10³⁴ bacteria at the end of 24 hours.

3 0

3 years ago