To solve this, we have to find the volume of the cylinder first. The formula to be used is

Given:V= ?r= 6cmh= 10cm
Solution:

V= (3.14)(6cm)

x 10cmV= (3.14)(

) x 10cmV= (

) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Answer:
624,600
Step-by-step explanation:
624,612
612 rounds to 600
624,600
F(x) - g(x) =
x^1/2 - (2x^3 - x^1/2)=
x^1/2 - 2x^3 + x^1/2=
2x^1/2 - 2x^3
The correct answer would be D, the median 86.5.
In this set of data most of the values are in the 80's or 90's. There is only 1 number that is outside of this range, that is the value 0. It is an outlier.
When we have an outlier, the median generally gives us the better measure of central tendency.