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lawyer [7]
3 years ago
13

Simplify 8 to the power of P times 3

Mathematics
1 answer:
elixir [45]3 years ago
5 0

Answer: 24^p

Step-by-step explanation:

8 ^p x 3

To simplify the above, multiply the whole numbers

8 x 3 = 24

24^p

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Multiple Choice question
liubo4ka [24]
My answer has to be B
3 0
3 years ago
Read 2 more answers
Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar
xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ_{e}^2 → S_{e} ^{2}), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

                        n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u>  915.8   </u>  = 16.067

                 20+20+20-3                  57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33

4. P(F_{2; 57} ≤ F) = P(F_{2; 57} ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0
3 years ago
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti
prohojiy [21]

ANSWER

Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

To proof

let us assume that the fluid should be drained and replaced with pure antifreeze be x .

As given

A radiator contains 10 quarts of fluid, 30% of which is antifreeze.

Now write 30% in the decimal form

= \frac{30}{100}

Now write 60% in the decimal form

= \frac{60}{100}

After  drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )

The quantity of  antifreeze is

= \frac{30\times (10 - x)}{100}

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

than the equation becomes

= x + \frac{30\times ( 10 - x )}{100} = \frac{60\times10}{100}

solyving

100x +300 - 30x = 600

70x = 300

x = \frac{300}{70}

x = 4.28 quarts (approx)

Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

Therefore the option (c.) is correct .

3 0
3 years ago
Read 2 more answers
Help for brainlist :)))
SVETLANKA909090 [29]

Answer:

<em>dear </em><em>option</em><em> </em><em>C </em><em>(</em><em>2</em><em>,</em><em>4</em><em>,</em><em>6</em><em>)</em><em> </em><em>is </em><em>correct</em><em> </em><em>for </em><em>this </em><em>question</em>

<em>as,</em>

<em>domain </em><em>=</em><em> </em><em>is </em><em>all </em><em>set </em><em>of </em><em>input </em><em>values</em>

<em>and</em>

<em>range </em><em>=</em><em> </em><em>is </em><em>all </em><em>set </em><em>of </em><em>output </em><em>value</em>

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>u </u></em><em><u>dear!</u></em>

4 0
3 years ago
0÷x=0<br> pls help it has to be 0 but thats not the answer can't think of anything
sleet_krkn [62]

Answer:

Theres no other answer than 0.

Step-by-step explanation:

I'm sorry!

4 0
3 years ago
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