<span>To be alive an organism must be able to intake nutrients, respirate, grow, and reproduce.</span>
Answer:
Following are some of the possible consequences of mutations:
1. Some of the mutations take place in proteins that play an essential role in the function of cells, and thus, the cell dies.
2. Some mutations result in the origination of new traits like red hair.
3. Some mutations take place in genes, which monitor the division of cell and thus cells start to divide out of control, resulting in cancer.
4. Some of the mutations may be beneficial and may offer some benefit to the organism in some of the environments. These advantageous mutations may be encouraged by natural selection and are the basis for the evolution of life on Earth.
1. Platypus, Brown Bear, Lion, and House Cat.
2. Brown Bear.
3. House Cat.
In this graph you are basically going down the line (or up towards the house cat) looking at the qualities each animal has. So whatever is on the bottom (hair and mammary glands) all animals above it has it. If the quality passes the animal, the animal doesn’t have that quality.
Hopefully this explanation is clearer with the answers.
Pioneer species are the first species that colonize places where there were previously no other living organisms, such as algae that colonize bare rocks. ... Therefore, they pave the way for other species to establish themselves at the location through the creation of new potential ecological<span> niches.</span>
Answer: For three traits inherited in a dominant/recessive pattern, the probability of an offspring in a trihybrid cross between parents heterozygous for all three traits to be recessive at exactly two of the three loci is 23/64.
Explanation: Let A, B and C represent the dominant alleles and a, b and c represent the recessive alleles. The genotype of each of the parent will be AaBbCc since it has been said to be heterozygous for all the three traits. There are eight (8) possible different types of gametes from each of the genotype. This can be calculated using 2^n where n is the number of heterozygous loci.
The number of heterozygous loci in the genotype AaBbCc is three (3). 2^3 = 8. The gametes are;
ABC
ABc
AbC
Abc
aBC
aBc
abC and
abc.
Therefore, sixty-four possible offsprings are expected from the cross AaBbCc x AaBbCc.
Out of these offsprings, twenty-three (23) are expected to be heterozygous at two loci as boldly shown in the attached image.
