The area of A'B'C is 6.25 times the area of ABC. Also it wouldnt hurt the report the guy below who's obviously milking points.
Sorry this just got deleted :( ill post it again

= 7
I'm sorry I'm bad at explaining how i solved it
We can start to solve this problem like how we solve any division problem. Since 8 doesn't go evenly into 4, we can move one digit to right, giving us the number 42. 42 divided by 8 is 5, so we write 5 on top of the division bar and keep working. Since 42-40 is 2, there's still 2 remained after doing that. Now we can bring down the 6, turning the number into 26. 26 divided by 8 is 3 remained 2, so we can put the three next to the 5. Since we have two remained and no more numbers, that means that the answer to 426/8 is 53 remainder 2.
Answer:
a = -2
Step-by-step explanation:
-(5a+6)=2(3a+8)
-5a -6 = 2*3a +2*8
-5a -6 = 6a +16
-5a -6a = 16+6
-11a = 22
a= -22/11
a = -2