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2 years ago

What is the vertex form of y=x^2-6x+6

Mathematics

2 answers:

soldier1979 [14.2K]2 years ago

7 0

$y=x^2-6x+6\\y=x^2-6x+9-3\\y=(x-3)^2-3$

andrezito [222]2 years ago

3 0

Answer:

y = (x - 3)² - 3

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

add/subtract (half the coefficient of the x- term )² to x² - 6x

Given

y = x² - 6x + 6

= x² + 2(- 3)x + 9 - 9 + 6

= (x - 3)² - 3 ← in vertex form

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mote1985 [20]

Triangle RST has vertices:

R(-4,2)

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T(-4,-4)

Then, the triangle is moving to the left you subtract the number of units from the x coordinates of each vertex of the triangle.

And the triangle is moving down, you subtract the number of units moved down from the y coordinates of each vertex. So:

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For T'

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Answer:

$\begin{gathered} R^{\prime}(-7,-2) \\ S^{\prime}(0,1) \\ T^{\prime}(-7,-8) \end{gathered}$

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