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Elis [28]
2 years ago
5

What is the vertex form of y=x^2-6x+6

Mathematics
2 answers:
soldier1979 [14.2K]2 years ago
7 0

y=x^2-6x+6\\y=x^2-6x+9-3\\y=(x-3)^2-3

andrezito [222]2 years ago
3 0

Answer:

y = (x - 3)² - 3

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

add/subtract (half the coefficient of the x- term )² to x² - 6x

Given

y = x² - 6x + 6

  = x² + 2(- 3)x + 9 - 9 + 6

  = (x - 3)² - 3 ← in vertex form

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Answer:

B= 90

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Step-by-step explanation:

So let’s start with the bottom angles.

We know that the adjacent angles in a parallelogram add up to 180° so our equation would be (b-10) + (b+10)=180. So let’s simplify it b and b are both the same variables so we will get 2b and -10 + 10 is 0 so we get the following equation 2b=180.

So now we divide 180 and 2 and we get 90 as b.

So one side will be 100 because of the +10 and the other 90 because of the -10.

Now for the next side.

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So we know that b+10 is adjacent to c so 180-100 is 80, so 80 is c.

Now for d.

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