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Maurinko [17]
3 years ago
5

What fraction of 11 and 1/6 in decimal form​

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0
11.16 repeat only the six is repeating
Tasya [4]3 years ago
3 0

Answer:

11.16 (6 is repeating)

Step-by-step explanation:

11 and 1/6

= 11•6+1 / 6

= 67/6

=11.16 (6 is repeating)

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A pair of shoes cost $120 but they are 25% Off;
Sever21 [200]

Answer:

Discount = $30, Final price = $90

Step-by-step explanation:

25% is one quarter. 120/4=30

One quarter of 120 is 30, so - 30 would give discounted price of $90.

Similarly you could think of it like the discounted price is 75% of the original one and do 120x0.75=90 to find 75% of 120.

Hope this helped!

3 0
4 years ago
7233 divided by 164 equals
stepan [7]
7233/164=44.10
..........

7 0
3 years ago
PLZ HELP ME I WAS STUCK ON THIS FOR 30 MINS WILL GIVE BRAINLIST
SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

6^3 is the error, 6^3 is 216.

the correct volume is   904.32

4 0
3 years ago
Read 2 more answers
A game of football consists of a total playing time of 90 minutes and a break of 15 minutes at half time.A football match begins
german
4:45 pm the match will end
4 0
2 years ago
The function h represents the height of an object t seconds after it is launched into the air. The function is
nasty-shy [4]

Step-by-step explanation:

h(t) = -5t² + 20t + 18

this is a parabola (the curve an object follows when thrown up into the air and then falling back down).

and as such it will most likely have 2 solutions (one for when going up, and one for when falling back down again).

33 = -5t² + 20t + 18

15 = -5t² + 20t

-3 = t² - 4t

t² - 4t + 3 = 0

the solution of such a quadratic equation is

t = (-b ±sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -4

c = 3

t = (4 ±sqrt(16 - 4×1×3))/(2×1) = (4 ±sqrt(16-12))/2 =

= (4 ±sqrt(4))/2 = (4 ± 2)/2

t1 = (4+2)/2 = 6/2 = 3

t2 = (4-2)/2 = 2/2 = 1

the object reaches the height of 33 m first after 1 second (while going up), and then again after 3 seconds (while falling down again).

7 0
2 years ago
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