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BlackZzzverrR [31]
3 years ago
6

Can someone please help mee :)

Mathematics
1 answer:
Lunna [17]3 years ago
5 0
Simplify the complex fractions
A) (from the picture) = 1 2/5.
B) (from the picture) = 13/22
Solve each equation below
A) (from the picture) x= 9
B) (from the picture) w= 10 1/2
C) (from the picture) y= -80
Find the sum of each number below. Describe how you know what the sign of you answer will be.
A) -19 + 8 = -11
B) -6 + (-5) = -11
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I need help please explain your work for number 7 only
Keith_Richards [23]

Answer:

Transitive property

Step-by-step explanation:

When a=c and b=c, a=b

A would be 16+43

B would be 59

C would be 10+49

5 0
2 years ago
How I can get the answer could you please tell me ?
valentina_108 [34]
Look it up after opening up a new tab

6 0
3 years ago
The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consume
AfilCa [17]

Answer:

Yes. The male and female consumers differ in the amounts they spend.

Step-by-step explanation:

We can express the null and alternative hypothesis as:

H_0: \mu_m=\mu_w\\\\H_1:  \mu_m\neq\mu_w

It is assumed a significance level of 0.05.

The standard deviation of the difference of means is calculated as:

s=\sqrt{\frac{s_m^2}{n_m} +\frac{s_w^2}{n_w} } =\sqrt{\frac{35^2}{40} +\frac{20^2}{30} } =\sqrt{30.625+13.333} =\sqrt{43.958} =6.63

The test statistic is

t=\frac{(M_m-M_w)-0}{s}=\frac{135.67-68.64}{6.63}=10.11

The degrees of freedom are:

df=n_1+n_2-2=40+30-2=68

The P-value for t=10.11 is P=0, so it is smaller than the significance level. The null hypothesis is rejected.

We can conclude that male and female consumers differ in the amounts they spend.

5 0
3 years ago
Margo borrows $1100, agreeing to pay it back with 8% annual interest after 9 months. How much simple
Leokris [45]

Answer: I wrote the answer in docs so here is the pic for the whole equation i explained it too! I hope this helped

7 0
2 years ago
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin
yarga [219]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=3\\ k=-7 \end{cases}\implies y=a(x-3)^2-7\qquad \textit{we also know that} \begin{cases} x=1\\ y=-10 \end{cases} \\\\\\ -10=a(1-3)^2-7\implies -3=a(-2)^2\implies -3=4a\implies -\cfrac{3}{4}=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-\cfrac{3}{4}(x-3)^2-7~\hfill

5 0
1 year ago
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