Ask question

Ask question

All categories

3 years ago

11

A 440 m long road is being repaired. After one day, the workers had repaired 3/4 of the road. What is the length of road left to

be repaired?

1 answer:

Nezavi [6.7K]3 years ago

3 0

440/4=110

110*3=330

330/440 = 3/4

They have repaired 330 meters of the road

You might be interested in

What is 66% of 75? <br> 25 <br> 33 <br> 40 <br> 49.5 <br> 66

Alja [10]

49.5 is the answer because 66% equals 2/3.

5 0

3 years ago

Read 2 more answers

Ja'kniya and Alayjah are shopping at the Apple Store. Ja'kniya bought 4 screensavers and 3 Otterboxes for $29. Alayjah bought 6

Katarina [22]

Answer: Each screensaver costs $2 and each Otterbox costs $7.

Step-by-step explanation:

Let x = Cost of each screensaver and y = cost of each Otterbox.

As per given, 4x+3y=29 (i)

6x +2y = 26 (ii)

Divide both sides of (i) by 2 and the multiply it by 3 on sides , we get

9x+3y=39 (iii)

Eliminate (i) from (iii) , we get

5x = 10

⇒ x = 2 [Divide both sides by 5]

Put value of x in (i), we get

4(2)+3y=29

⇒ 8+3y= 29

⇒ 3y= 21

⇒ y =7 [Divide both sides by 7]

Hence, Each screensaver costs $2 and each Otterbox costs $7.

7 0

3 years ago

Is 10.10 greater than 10.01?

kolbaska11 [484]

Yes, it is 0.09 grater that 10.01

5 0

4 years ago

Read 2 more answers

What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0

3 years ago

Let f(x)=-2x+7 and g(x)=x^2+9 find f(5)+g(5)

trapecia [35]

Substitute 5 into both the equations...
-2 (5)+7=-3
5^2+9=34

-3+34=31
hope this helpsss

7 0

3 years ago