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erica [24]
3 years ago
10

PLS HELP U WILL GET BRAINLIEST

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

The 1st option

Step-by-step explanation:

Line RT bisects VS at a right angle. We know that angle RTS is a right angle, so RTV is also a right angle.

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3 years ago
Due tonight.. *no links*
Oliga [24]

Answer:

Step-by-step explanation:

Sum of interior angles of a polygon formula:

180 (n - 2)

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180 (20 - 2) = 3,240

4 0
3 years ago
IQ scores on the WAIS test approximate a normal curve with a mean of 100 and a standard deviation of 15. What IQ score is identi
riadik2000 [5.3K]

Answer:

IQ scores of at least 130.81 are identified with the upper 2%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 100 and a standard deviation of 15.

This means that \mu = 100, \sigma = 15

What IQ score is identified with the upper 2%?

IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.

Z = \frac{X - \mu}{\sigma}

2.054 = \frac{X - 100}{15}

X - 100 = 15*2.054

X = 130.81

IQ scores of at least 130.81 are identified with the upper 2%.

7 0
3 years ago
If f(x) is a linear function and the domain of f(x) is the set of all real numbers, which statement cannot be true?
IRISSAK [1]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Which point is located at 2 7/10 PLEASE ANSWER QUICK
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C, with the ten segments and moving over seven of them you will land on C.

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2 years ago
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