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Savatey [412]
3 years ago
13

Each grade level at hooperville schools has 298 students

Mathematics
2 answers:
Afina-wow [57]3 years ago
7 0
The answer is... 23 hooverville schools
Dvinal [7]3 years ago
3 0
There would be 3874 students

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Me is extremly dum 1st grader so wats 2+_=748
erik [133]

Answer:

The answer should be 746

Please rate this!!

7 0
3 years ago
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The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt
AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

                             P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average height = 175 cm

            \sigma = population standard deviation = 20 cm

            n = sample of men = 40

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the true mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                     level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times }{\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times }{\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for </u>\mu = [ \bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 175-1.96 \times }{\frac{20}{\sqrt{40} } } , 175+1.96 \times }{\frac{20}{\sqrt{40} } } ]

                                            = [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

<em>The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.</em>

3 0
3 years ago
Cuales de las expresiones son equivalentes a 2(4f+2g)?
Elena L [17]

Answer:

8f+4g

Step-by-step explanation:

2•4f=8f, 22g=4g, 8f+4g=8f+4g

8 0
4 years ago
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Juno ams Akima are training for a blathlon together. They are going to jog for the same amount of time as each other every day w
alexgriva [62]

Answer:3 hours

Step-by-step explanation:

Juno jogs at rate of 6 miles and bikes at rate of 14 miles covering total of 48 miles.

Akima jogs at rate of 8 miles and bikes at rate of 12 miles covering total of 44 miles.

Let jogging be represented by j

Let biking be represented by b

For Juno, 6j + 14b = 48 ......... i

For Akima, 8j + 12b = 44.......... ii

Multiply equation I by 8

Multiply equation ii by 6

48j + 112b = 384 ........... iii

48j + 72b = 264 ............. iv

Subtract equation iv from iii

48j + 112b = 384

- 48j + 72b = 264

40b = 120

b = 120/40

b = 3

Number of hours spent biking is 3 hours.

7 0
4 years ago
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Evaluate 6 to the power of -2
alex41 [277]

Answer:

1/36

Step-by-step explanation:

6^-2 = 1/6^2 = 1/36.

7 0
4 years ago
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