Answer:
baby #1 goes to family 2
baby #3 goes to family 1
and baby #2 goes to family 3
Explanation:
its simpler then it looks☺
If a particular job of a cell was to swim a long distance to an egg with a flagella, then it would need more mitochondria. As mitochondria undergo cellular respiration and essentially utilize the carbohydrates for that particular cell to produce the final product of ATP high energy containing molecules needed for the movement.
The answer to this question is a
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
