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expeople1 [14]
3 years ago
14

Find the circumference of a circle with a radius of 5.3 cm. Round to the nearest hundredth

Mathematics
2 answers:
Viktor [21]3 years ago
6 0

radius=5,3

r=5,3

circuit=2πr

O=2π*5,3

<u>O=10,6π</u>

Rzqust [24]3 years ago
4 0

Answer: 33.3

Step-by-step explanation: 5.3 x 6.28 = 33.284 = 33.3

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The sum of two numbers is ten. the difference between them is 8 . find the two numbers
alexira [117]

x+y=10

x-y=8, x=y+8

y+8+y=10

2y=2

y=1

So, x=10-y=10-1=9.

Numbers Would be 9 and 1.


3 0
3 years ago
The circles are identical. What is the circumference of each circle? Circle 1: radius of 2x; Circle 2: diameter of 2x+3. A. 3/2
Delicious77 [7]

Answer:

C=6π

Step-by-step explanation:

It is given that, two circles are identical. The radius of first circle is 2x and the diameter of other circle is 2x+3.

If identical, it means that the radius of both circles are same i.e.

2x=\dfrac{2x+3}{2}\ \ (\because\ r=\dfrac{D}{2}, d=\text{diameter})\\\\4x=2x+3\\\\2x=3\\\\x=1.5

Radius of both circles is 2(1.5)=3

The circumference of a circle is given by :

C=2\pi r\\\\C=2\pi (3)\\\\C=6\pi

So, the circumference of each circle is 6π.

7 0
2 years ago
Based on the given segment lengths, determine whether the segments can form a triangle.
murzikaleks [220]

For 3 sides to form a triangle two sides added together need to be greater then the 3rd side. You need to check all 3 combinations:

1. 11.5 + 10.5 = 22, 22> 6.1

11.5 + 6.1 = 17.6 17.6 > 10.5

10.5 + 6.1 = 16.6, 16.6 > 11.5

This one can make a triangle.

2. 9.5 + 3.5 > 4.5

9.5 + 4.5 > 3.5

4.5 + 3.5 < 9.5

Cannot make a triangle.

3. 8 + 6.7 > 1

6.7 + 1 < 8

Cannot make a triangle.

4. Can make a triangle

5. Can

6. Can

4 0
3 years ago
Find tan 0<br> 16<br> 20<br> 12<br> A.<br> 19<br> B.<br> D.<br> 20
lisov135 [29]

Answer:

Answer is 16/12

Step-by-step explanation:

Tan is Opposite by Adjacent. the opposite side is 16, adjacent side is 12 and hypotenuse is 20.

so O/A= 16/12

8 0
2 years ago
Read 2 more answers
Algebra 1. Please show work.
MAVERICK [17]
Try this:
Given:
\left \{ {{x-y=1} \ [1] \atop {x+y=3} \ [2]} \right.
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)
7 0
2 years ago
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