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3 years ago

What is the value of the expression 2^2+4^2 divided by 2^2

Mathematics

1 answer:

N76 [4]3 years ago

5 0

Use PEMDAS:

Parentheses

Exponents

Multiply and Divide from left to right.

Add and Subtract from left to right.

-------------------------------------------------------

Evaluate the exponents.

2^2+4^2/2^2

Divide from left to right.

4 + 16/4

Add from left to right.

4 + 4

Solution.

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ABCD ~ WXYZ. AD = 6, DC = 3, and WZ = 59. Find YZ.

dusya [7]

You take alll the answers and just divide each one

5 0

3 years ago

The daily profit P (in thousands of dollars) from the sale of televisions is a function of the number x of televisions sold (

scZoUnD [109]

Answer:

The break-even sales amounts is 36 or 224.

Step-by-step explanation:

Consider the provided function.

$P= -5x^2 + 13x - 4$

Where x is the number of televisions sold (in hundreds) and P is the profit.

We need to calculate the break-even sales amounts.

the break-even sales amounts is the sales amounts that result in no profit or loss.

That means substitute P=0 and solve for x.

$-5x^2 + 13x - 4=0$

$5x^2-13x+4=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a=4, b=-13 and c=4 in above formula.

$x_{1,\:2}=\frac{-\left(-13\right)\pm \sqrt{\left(-13\right)^2-4\cdot \:5\cdot \:4}}{2\cdot \:5}$

$x_{1,\:2}=\frac{13\pm\sqrt{169-80}}{10}$

$x_{1,\:2}=\frac{13\pm\sqrt{89}}{10}$

$x=\frac{13+\sqrt{89}}{10},\:x=\frac{13-\sqrt{89}}{10}\\x\approx2.243, \ or\ x\approx 0.357$

Therefore, the break-even sales amounts is 36 or 224.

7 0

3 years ago

Can someone help plz :')

olga_2 [115]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please help with this Math Question...

Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 | 1 4 7 6

1 2 3 0 ← remainder is 0 so x = -2 is a root ⇒ (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}$

$x=\dfrac{-2\pm\sqrt{4-12} }{2}$

$x=\dfrac{-2\pm\sqrt{-8} }{2}$

$x=\dfrac{-2\pm2i\sqrt{2}}{2}$

$x = -1 \pm i\sqrt{2}$

$x = -1 + i\sqrt{2}$ $x = -1 - i\sqrt{2}$

$x - (-1 + i\sqrt{2})=0$ $x - (-1 - i\sqrt{2})=0$

The factors are:

$(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]$

5 0

3 years ago

THIS IS URGENTE I AM BEING TIMED PLZ HELP, if you answer both correct i will mark you brainlyist

Lapatulllka [165]

Area would be 4.52 A= pi x radius squared
Circumference would be 7.54 C= 2 pi radius. Hope that makes sense.

4 0

3 years ago