PLEASE HELP ASAP!!! *problems attached

Science is Hayley's favorite class! She especially loves doing experiments. Today, she began

raketka [301]

Answer: the final mass of the solid is 176 grams.

Step-by-step explanation:

The "change" between two quantities, one initial Qi and one final Qf is defined as:

Change = Qf - Qi.

In this case, the quantity is mass, and we know that the initial mass is 260 grams.

And we also know that the change is -84 grams.

Then we have the equation:

Qf - 260 g = -84g

Qf = -84g + 260g = 176g

So the final mass of the solid is 176 grams.

8 0

2 years ago

the mathematics Department of a college has 11 male professors 12 female professors 9 male teaching assistants and 12 female tea

Marta_Voda [28]

Answer:

P(teaching assistant or a female) = 1 - P(professor and male) = 1 - 11/44 = 1 - 0.25 = 0.75

Make a Contingency_table

7 0

3 years ago

Please help!!! Select the quadratic equation that has no real solution.

ad-work [718]

Answer:

2x² + 6x + 20

Step-by-step explanation:

See the picture

6 0

2 years ago

PLEASE HELP What is the value of x?

AleksAgata [21]

The angles inside a triangle add up to 180°
The 3rd angle is supplementary to (6x+1)°
Supplementary means they make a straight line (i.e 180°)

1st angle = 79°
2nd angle = (2x+10)°
3rd angle = 180° - (6x+1)°

180 = 79 + (2x+10) + 180 - (6x+1)
180 = 79 + 2x + 10 + 180 - 6x - 1
combine like terms
180 - 180 - 79 - 10 + 1 = 2x - 6x
-88 = -4x
-88/-4 = x
22 = x

3 0

3 years ago

Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs

Fudgin [204]

Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

$Length: 10\ in$

$Width: 8\ in$

Required

Determine the possible dimensions of Rectangle B

The question has missing options; however, the question can still be solved.

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

$Length: 15 in$

$Width: 12 in$

Divide the corresponding lengths of B by A to get the enlargement ratio

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{15}{10}$

$Ratio = 1.5$

For width

$Ratio = \frac{12}{8}$

$Ratio = 1.5$

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

$Length: 20\ in$

$Width: 10\ in$

Calculate Ratios

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{20}{10}$

$Ratio = 2$

For width

$Ratio = \frac{10}{8}$

$Ratio = 1.25$

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy

5 0

3 years ago