Answer:
<h2> In 8 hours he will set 1200 bricks</h2>
Step-by-step explanation:
In this problem, we are expected to estimate the number of bricks he can set in 8 hours.
let us convert hours to minutes we have
60 min make 1 hour
x min make 8 hours
cross multiply
x= 60*8
x= 480 min
We are assuming the same rate with which he sets 2.5 brick is the same as the rate with which he will set bricks for the 8 hours windows
so if the bricklayer sets
2.5 bricks in 1min
y bricks in 480 min
Cross multiply we have
y=2.5*480
y= 1200 bricks
hence in 8 hours, he will set 1200 bricks
What is the base salary for the Bit Labs?
Hours of training Monthly salary
10 1250
20 1400
30 1550
40 1700
50 1850
60 2000
70 2150
Answer:
a) 50.24 ft²
b) 150.72 ft²
Step-by-step explanation:
Jason is painting a large circle on one wall of his new apartment. The largest distance across the circle will be 8 feet.
The distance across a circle is also called a diameter, Hence,
D = Diameter = 8 ft
The Area of a circle = πr²
r = Diameter/2 = 8ft/2 = 4ft
π = 3.14
Hence,
The Area of the circle = π × (4 ft)²
= 50.24 ft²
a) Approximately the amount of wall the circle will cover is 50.24 ft².
b) How much area will he cover if he painted a circle on three walls?
This is calculated as:
1 wall = 50.24 ft²
3 walls = x
Cross Multiply
x = 3 × 50.24 ft²
x = 150.72 ft²
Answer: The answer is A
Step-by-step explanation: You use normalcdf to find the area under a curve. The lower bound (in this case 7) goes first followed by the upper bound, mean, and standard deviation.
Answer:
Step-by-step explanation:
we know that
In this problem we have a exponential function of the form
where
a is the initial value or y-intercept
b is the base of the exponential function
r is the rate in decimal form
b=(1+r)
In this problem we have
x ----> the number of days
y ----> the number of shoppers
a=120
r=10%=10/100=0.10
b=1+0.10=1.10
substitute the values
First day
Second day
For x=1 day
substitute the value of x in the equation and solve for y
Third day
For x=2 days
Fourth day
For x=3 days
Fifth day
For x=4 days
Sixth day
For x=5 days
Seventh day
For x=6 days
Adds the numbers
