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Stells [14]
3 years ago
9

Helppppppp....!!??!!!

Mathematics
1 answer:
andrew-mc [135]3 years ago
7 0
I think the answer is B because a perpendicular bisector is 90 degrees and an angle bisector divides that angle by 2. 90 divided by 2 is 45, so the answer is B.
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Please help with this
Tanya [424]

Answer:

Step-by-step explanation:

y = mx + b

Take any two points and set up 2 equations with 2 unknowns.

I'll start with the first two

y = 4x + b

410 = 4x + b                    (1)

440 = 6x + b                   (2)

Subtract (1) from (2)

440 = 6x + b

<u>410 = 4x + b</u>            Subtract

30  = 2x                  Divide by 2

30/2 = 2x/2

x = 15

440 = 6(x) + b

440 = 6*15 + b

440 = 90   + b

b = 350

Now here is what you found.

Her base salary is 350 dollars

Each television she sells brings her an addition 15.

3 0
3 years ago
(c³d)a(cd⁷)a<br>Simplify <br>​
Veseljchak [2.6K]

Answer:

= c^4 d^8 a^2

Step-by-step explanation:

Apply exponent rule: aa= a^2

= c^3 da^2 cd^7

= c^4 da^2 d^7

= c^4 d^8 a^2

5 0
3 years ago
8,508,400 divided by 10 to the sixth power
irga5000 [103]
Your answer for your problem

4 0
3 years ago
A quadratic function f(x)f(x) is hidden from view. You must find the xx-intercept(s) of f(x)f(x) and write the answer(s) in the
Alika [10]

f(x) should be in canonical form. So it must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient and is the vertex

Step-by-step explanation:

A quadratic function has a unique extreme value in its vertex. That value might be a maximum or a minimum depending on the sign of the main coefficient of the quadratic function. In order to quickly obtain the vertex, the quadratic must be written in canonical form. That means that f(x) must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient (which should be negative so that a minimum exists in the first place) and is the vertex. If f(x) is written in that form, then it will be easier to find the minimum of f(x), which is the vertex

Hence for the quadratic function below

\begin{gathered} f(x)=(x-2)^2-9 \\ f(x)=x^2-4x-5 \\ ax^2+bx+c \\ a=1,\text{ b=-4, c=-5} \\ x_v=-\frac{b}{2a} \\ x_v=\frac{-(-4)}{2(1)} \\ x_v=\frac{4}{2} \\ x_v=2 \\ y_v=2^2-4(2)-5 \\ y_v=-9 \\ (x,y)\longrightarrow(2,-9) \end{gathered}

Hence there is only one x- intercept and answer is (2, -9)

7 0
2 years ago
Which function below grows at the fastest rate for increasing values of x?
Elina [12.6K]
C? I'm not sure. It seems like the most reasonable answer.
6 0
3 years ago
Read 2 more answers
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