The depth of the water at the <em>deepest</em> point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)
<h3>How to determine the depth of the water in a waterslide</h3>
In this question we should apply the concepts of <em>right</em> triangles and <em>trigonometric</em> functions to determine the height of the water within the waterslide. A geometric diagram of the <em>cross</em> section of the waterslide is presented below, which indicates the existence of <em>circular</em> symmetry.
Now we proceed to determine the height of the water:
cos α = (0.5 m/0.75 m)
α ≈ 48.190°
y = (0.75 m) · sin 48.190°
y = 0.559 m
x = 0.75 m - 0.559 m
x = 0.191 m
The depth of the water at the <em>deepest</em> point in the waterslide and to the nearest hundredth of a meter is approximately 0.19 meters. (Correct choice: A)
To learn more on trigonometry: brainly.com/question/22698523
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If you could attach a picture I would be more than happy to help.
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Answer:
For x-2y=15, it's x= 15 + 2y. For 2x+4y=-18, it's x= -9-2y.
Step-by-step explanation:
Answer:
y = 3x
Step-by-step explanation:
slope of line = 3
passing through = (0, 0)
The equation of line passing through a point and the slope is given is
y - 0 = 3 (x - 0)
y = 3 x
Thus, the equation of line is given by y = 3 x.