The genotypes would be bbTT X BbTt
Assuming that bark color is represented by B (b) allele and height is represented by T (t) allele.
Since the traits show simple dominance: blue (B) of dominant over purple (b) and tall (T) is dominant over short (t)
- The genotype of a tree that is purebred purple (bb) and tall (TT) would be bbTT
- The genotype of a tree that is heterozygous for both trait would be BbTt
- Thus, the cross would be bbTT x BbTt
More on genotypes can be found here: brainly.com/question/20730322?referrer=searchResults
Answer:
flexion
Explanation:
The flexion is a movement of the body part that is described the bending of an elbow, or the clenching a hand into a fist, etc. where the angle between any segment of the body and its proximal segment decreases.
In simple words, the flexion is a movement which decreases the angle between two body parts when they are moved.
The flexion occurs in the sagittal plane.
Thus, the movement of a thumb that would be mostly affected by the lesion of median nerve in cubital fossa is the flexion movement.
If it’s DNA than the transcription is TCTAACTGT
If it’s RNA than it’s UCUAACUGU
