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Brut [27]
3 years ago
10

The process of mRNA processing eukaryote is modeled above. what does the addition of the poly-A tail provide for the cell?

Biology
2 answers:
rewona [7]3 years ago
8 0

Answer:

D) Poly-A tails allow eukaryotic cells to export their mRNA from the nucleus and prevent the degradation of the mRNA in the cytoplasm.

Explanation:

tangare [24]3 years ago
7 0

Answer:

D

Explanation:

An enzyme called poly (A) polymerase (PAP) is part of the same protein complex that cleaves the pre-mRNA and it immediately adds a string of A nucleotides, called the poly (A) tail, to the 3′ end of the just-cleaved pre-mRNA. The poly (A) tail added protects the mRNA from degradation, aids in the exportation of the mature mRNA to the cytoplasm and helps in binding proteins involved in initiating translation.

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7 0
3 years ago
Which of the following is NOT true of
stich3 [128]

They aren't all the same is not true of evolutionary trees.

<h3>What are evolutionary trees?</h3>

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6 0
2 years ago
Why is there a gap or synapse between the nerve endings why can't itbe joined to the other nerve?
MariettaO [177]
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3 0
3 years ago
Both of them I am very stuck on
Levart [38]

Answer:

25. red

24. A. Temperature and Luminoscity

Explanation:

3 0
3 years ago
one gene in a population of snails determines whether they are poisonous. being poisonous (P) is dominant over not being poisono
Harlamova29_29 [7]

Answer:

F (pp) = 0.04

F (Pp) = 0.32

F (PP) = 0.64

Explanation:

Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.

If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.

This means that 0.04 corresponds to p², and p corresponds to 0.2.

Therefore, P is equal to 0.8 because p + P = 1.

Knowing the allele frequencies, we go to the frequency of the genotypes.

F (pp) = p² = 0.04 = 8 snails

F (Pp) = 2.Pp = 0.32 = 64 snails

F (PP) = P² = 0.64 = 128 snails

7 0
3 years ago
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