<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
20%
Step-by-step explanation:
14/70x100=20%
∑ Hey, jillianwagler ⊃
Answer:
Step-by-step explanation:
<u><em>║Given info║:</em></u>
<em>Factor completely: </em>
<u><em>Solution~:</em></u>
<em>Breaking the expression~: </em>
<em>Factor out 2x from 4x² -2x : 2x(2x-1)</em>
<em>Factor out 5 from 10x - 5 : 5(2x - 1)</em>
<em>Put together: </em>
Factor out 2x - 1: 
<u><em>xcookiex12</em></u>
<em>8/19/2022</em>
Answer:
It has none. Angle A is obtuse, so it would have to be opposite the longest side. If side a is opposite angle A, then that is not the case.
Step-by-step explanation:
Answer:
10657.5
Step-by-step explanation:
<h2>
Long way that is unnecessarily long</h2>
We can start by finding the area of the larger triangle. Using the Pythagorean theorem, we can say that 251²-105²=the bottom side², and 251²-105²=51976, so the bottom side of the larger triangle is √51976 , or approximately 228. Then, the area of the larger triangle is √51976 * 105/2 = 11969 (approximately). Then, the area of the smallest triangle (the largest triangle - the one that we're trying to find the area of) is 105*(√51976-203)/2 = approximately 1312. Then, subtracting that from the total area, we get (√51976 * 105 - 105*(√51976-203))/2 = 105*203/2 = 10657.5
<h2>Short way</h2>
ALTERNATIVELY, upon further review, we can just see that the height is 105 and the base is 203, so we multiply those two and divide by 2, as is the formula for the area of a triangle, to get 10657.5
