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Gwar [14]
3 years ago
13

67.943 in expanded form

Mathematics
2 answers:
mario62 [17]3 years ago
8 0
60 + 7 + 0.9 + 0.04 + 0.003
Komok [63]3 years ago
7 0
60+7+0.9+0.04+0.003
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Samantha invested $50,000 in an account paying an interest rate of 4.1% compounded daily. Assuming no deposits or withdrawals ar
Sever21 [200]

Answer:

$69,408.17  = $69,410 rounded

Step-by-step explanation:

Final investment value

$69,408.17

Total interest earned

$19,408.17

Initial balance

$50,000.00

Total monthly deposits

$0.00

Effective Annual Rate (APY)

4.185%

The formula used in the compound interest calculator is A = P(1+r/n)^(nt)

A = the future value of the investment

P = the principal investment amount

r = the interest rate (decimal)

n = the number of times that interest is compounded per period

t = the number of periods the money is invested for

7 0
3 years ago
Read 2 more answers
What is 13.55 in a mixed number in simplest form?
iris [78.8K]
I think its 13 11/20
3 0
4 years ago
Write an expression for the difference between 10 and x
Flauer [41]
The expression is 10-x=
8 0
4 years ago
What number is missing? explanation please
-BARSIC- [3]
The missing number is 12

because the pattern is that the the numbers below and to the right of a number equals that number. ex: 3+4=7. so in order to find the missing number you have to do the opposite of addition, which is subtraction. (17-5=12)
8 0
3 years ago
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Which of the following is equivalent to the expression 8/3 - 5/6 - 2/12
Vlad [161]

Given:

The expression is

\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{2}{12}

To find:

The expression which is equivalent to the given expression.

Solution:

We have,

\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{2}{12}

It can be written as

=\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{1}{6}

Taking LCM, we get

=\dfrac{16-5-1}{6}

=\dfrac{10}{6}

=\dfrac{5}{3}

The mixed fraction of this improper fraction is

=\dfrac{1\times 3+2}{3}

=1\dfrac{2}{3}

So, the expression 1\dfrac{2}{3} is equivalent to the given expression.

Therefore, the correct option is A.

8 0
4 years ago
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