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Mathematics

1 answer:

umka2103 [35]3 years ago

3 0

${t}^{2} = \frac{4b {x}^{2} }{k} \\ k {t}^{2} = 4b {x}^{2} \\ \frac{k {t}^{2} }{4b} = {x}^{2} \\ x = \sqrt{ \frac{k {t}^{2} }{4b} } = 0.5t \sqrt{ \frac{k}{b} }$

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Normal probability distribution

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