Question

Help me please right away​

Answer 1

${t}^{2} = \frac{4b {x}^{2} }{k} \\ k {t}^{2} = 4b {x}^{2} \\ \frac{k {t}^{2} }{4b} = {x}^{2} \\ x = \sqrt{ \frac{k {t}^{2} }{4b} } = 0.5t \sqrt{ \frac{k}{b} }$