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valentina_108 [34]
3 years ago
5

If x – 9 is a factor of x2 – 5x – 36, what is the other factor a. x – 4 b. x 4 c. x – 6 d. x 6

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0
X^2 -5x -36 = x*x -9x+4x -9*4 = x(x-9) +4(x-9) = (x+4)(x-9)

so the second other factor is x+4 so hope that choice wan being x+4 than this will be right just you missed the sign pf plus 

hope this will help you 
LekaFEV [45]3 years ago
5 0

Answer:

a ) Other factor will be ( x + 4 ) .

Step-by-step explanation:

Given :  x²– 5x – 36.if x – 9 is a factor

To find : what is the other factor .

Solution : We have given that x²– 5x – 36.= 0

On factoring x² +  4x - 9x– 36= 0

Taking common x from first two terms and -9 from last two terms .

x ( x + 4) -9 ( x + 4) = 0

on grouping

(x -9) ( x+4) = 0.

Therefore, a ) Other factor will be ( x + 4 ) .

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Answer:

true

Step-by-step explanation:

(-3)^22 -> to the power of an even number -> answer is positive

(-2)^33 -> to the power of an odd number -> answer is negative

positive # > negative #

7 0
2 years ago
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What is 5y+1 if y=6?
kipiarov [429]

Answer:

31

Step-by-step explanation:

5*6+1

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3 years ago
Mateo is training for a race. On Monday Mateo ran 7/10 mile. On Tuesday Mateo ran 9/10 mile. how much farther did Mateon run on
Valentin [98]

Answer:

\frac{1}{5}

Step-by-step explanation:

\frac{9}{10} -\frac{7}{10} =\frac{2}{10} =\frac{1}{5}

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3 years ago
Two numbers have prime factorizations of 2 2 · 3 · 5 and 2 · 3 2 · 7.
ladessa [460]
I think for the question above, instead of 2 · 3^2 · 7 it is <span>2 · 3^2 · 5.
</span>
Two numbers have prime factorizations of 2^2 • 3 • 5 and 2 • 3^2 • 5 (note 2 squared & 3 squared).

Now, to choose the GCF, you choose, for each base factor in either number, the least exponent-ed one; so the GCF needs a factor 2, a factor 3, and a factor 5. Thus the GCF is 30 (their product). [i.e,2 squared is not a common factor]

<span>To create the LCM, you choose, for each base factor in either number, the greatest exponented one. Thus, LCM needs a factor 2 squared, 3 squared, and 5, giving LCM = 4(9)(5) = 180.</span><span />
4 0
3 years ago
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Determine whether the following equation defines y as a function of x.
Aleks04 [339]

Answer:

The equation can define y as a function of x and it also can define x as a function of y.

Step-by-step explanation:

A relation is a function if and only if each value in the domain is mapped into only one value in the range.

So, if we have:

f(x₀) = A

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f(x₀) = B

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Now we want to see it:

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if we isolate y, we get:

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Now we also want to check if:

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So now we need to isolate x to get:

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