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2 years ago

Find the volume of this

Mathematics

1 answer:

11111nata11111 [884]2 years ago

4 0

Answer:

37.8 yd^3

Step-by-step explanation:

base area = (4.5 x 2.8)/2 = 6.3 yd^2

Volume = 6.3 x 6 = 37.8 yd^3

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13 POINTS! EVALUATE AND SHOW ALL WORK

padilas [110]

Answer:

Step-by-step explanation:

Solving in steps

3| 4.5 - 2| - 5 |-1.5 -(- 3)| =
3 |2.5| -5 |-1.5 + 3| =
3*2.5 - 5|1.5| =
7.5 - 5*1.5 =
7.5 - 7.5=
0

3 0

3 years ago

What is the part and whole of 40% of 20?

pashok25 [27]

The answer is 8

I hope this helps!

5 0

2 years ago

N/8= 25/40 N/20=85/100 2/3=16/n 5/6=25/n

4vir4ik [10]

N/8 = 25/40
40n = 25 * 8
40n = 200
n = 200/40
n = 5

n/20 = 85/100
100n = 85 * 20
100n = 1700
n = 1700/100
n = 17

2/3 = 16/n
2n = 16 * 3
2n = 48
n = 48/2
n = 24

5/6 = 25/n
5n = 25 * 6
5n = 150
n = 150/5
n = 30

3 0

3 years ago

Members of a softball team raised $1513.50 to go to a tournament. They rented a bus for $961.50 and budgeted $46 per player for

aniked [119]

Answer: 1513.50=961.50+46x

The number of players the team can bring to the tournament = 12.

Step-by-step explanation:

Let x= the number of players the team can bring to the tournament.

Total money raised = Rent of bus + (Cost per player) (Number of players)

$1513.50=961.50+46x\\\\\Rightarrow\ 46x=1513.50-961.50\\\\\Rightarrow\ 46x = 552\\\\\Rightarrow x=\dfrac{552}{46}\\\\\Rightarrow x=12$

Hence, the number of players the team can bring to the tournament = 12.

6 0

2 years ago

Learning the basics 6.23 suppose you select one value from a uniform distribution with a=0and b=10.what is the probability that

IgorC [24]

The area under the graph of the continuous uniform distribution is 1.
a. The probability that the value will be between 5 and 7 is the area between 5 and 7.
$P(5 \ \textless \ x \ \textless \ 7) = \frac{2}{10} = \frac{1}{5}$
b. The probability that the value will be between 2 and 3 is the are between 2 and 3.
$P(2 \ \textless \ x \ \textless \ 3)=\frac{1}{10}$
c. The mean is given by:
$\mu=\frac{a+b}{2}=\frac{0+10}{2}=5$
d. The variance is given by:
$\sigma^2}=\frac{1}{12}(b-a)^{2}=\frac{1}{12}(10)^{2}=8.3333$
The standard deviation is:
$\sqrt{\sigma} = \sqrt{8.3333} =2.887$

5 0

2 years ago