<h2>Thus the radius
is 1.2 m</h2>
Explanation:
The potential at point A due to point charge at center .
V₁ = = 7.2 x 10⁻⁸ x 9 x 10⁹ []
Similarly
The potential at B
V₂ = = 7.2 x 10⁻⁸ x 9 x 10⁹ [ ]
The potential difference
V = V₂ - V₁ = 648 [ - ]
The work done
W = q₀ V = 4.5 x 10⁻¹¹ x 648 [ - ]
But W = 8.1 x 10⁻⁹ J
Thus equation is
8.1 x 10⁻⁹ = 4.5 x 10⁻¹¹ x 648 [ - ]
0.28 = [ - ] or = 0.28 + 0.55 = 0.83
or = 1.2 m
The word to fill in the blank is "equal". Because the time taken to rotate (spin on its axis) is equal to the time of revolution (going around the earth), this means that both have the same rate of angular rotation. So for every bit that the moon goes around its orbit around earth, the moon itself rotates accordingly to present the exact same side to earth.
The momentum of both the identical balls would eventually be transferred to one another when it comes to a point wherein they will collide. In addition, the phenomenon is called an elastic collision wherein both the momentum and energy of the system would considered to be conserved.
Explanation:
It is given that,
Mass of an electron,
Electric field,
Separation between the plates, d = 1.9 cm = 0.019 m
The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate. We need to find the speed of the electron as it leave the hole.
The force due to accelerating electron is balanced by the electrostatic force i.e
qE = ma
Let v is the speed as it leave the hole. It can be calculated using third equation of motion as :
v = 9824459.27 m/s
or
So, the speed of the electron as it leave the hole is . Hence, this is the required solution.
Answer:
The number of turns of the inductor is 2000 turns.
Explanation:
Given;
emf of the inductor, E = 0.8 V
the rate of change of current with time, dI/dt = 10 A/s
steady current in the solenoid, I = 0.2 A
flux per turn, Ф = 8.0 μWb per
Determine the inductance of the solenoid, L
E = L(dI/dt)
L = E / (dI/dt)
L = 0.8 / (10)
L = 0.08 H
The inductance of the solenoid is given by;
Also, the magnetic field of the solenoid is given by;
I is 0.2 A
But Ф = BA
Therefore, the number of turns of the inductor is 2000 turns.